Math, asked by chinnari007, 8 months ago

two numbers are in ration 2:3 and their sum is 80 then the least is ______​

Answers

Answered by Anonymous
22

\huge\boxed { \fcolorbox{pink}{yellow}{Answer}}

Let the numbers be 2x and 3x

Their sum=80

2x+3x=80

5x=80

x=80/5

x=16

So, 2x=2(16)=32

3x=3(16)=48

So, least is 2x=32

Thanx

Answered by Anonymous
7

Given :

  • Two numbers are in the ratio of 2:3
  • Their sum is 80

To Find :

  • The smallest ( least ) number

Solution :

  • Let the unknown number be x , then the numbers becomes 2x and 3x

According to the question :

\:\:\: \implies \: \sf 2x\:+\:3x\:=\:80 \\

\:\:\: \implies \: \sf 5x\:=\:80 \\

\:\:\: \implies \: \sf x\:=\: \cancel \dfrac{80}{5} \\

\:\:\: {\red \bigstar \:  \large{\boxed{\sf{\pink{x\:=\:16}}}}} \\ \\

  • Numbers :

  1. 2x = 2(16) = 32
  2. 3x = 3(16) = 48

\bigstar \: {\sf{\underline{Therefore\:, \:least\:number\:is\:32}}} \\ \\

_________________________

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