Question

Two numbers are in the ratio 10:13. If the difference between the numbers is 48,find the numbers.

Answer 1

Let the numbers be 13x and 10x
ATQ,
13x-10x=48
3x=48
x=16
Numbers=208 and 160

Answer 2

Answer:

first, we have to subtract the ratios 13-x10 = 3x now, 3x= 48 = 16 10(16) and 13(16) = 160 and 208