Two numbers are in the ratio 2:3 and the difference of their squares is 320 the numbers are
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6
Condition 1: a/b = 3/2, or a=1.5*b
Condition 2: a^2 - b^2 = 320
a = 1.5*b, then (1.5b)^2 - b^2 = 320
(2.25 - 1)*b^2 = 320
b^2 = 320/1.25 = 256
b = 16
a = 1.5*b = 24
the numbers are 24 and 16.
Condition 2: a^2 - b^2 = 320
a = 1.5*b, then (1.5b)^2 - b^2 = 320
(2.25 - 1)*b^2 = 320
b^2 = 320/1.25 = 256
b = 16
a = 1.5*b = 24
the numbers are 24 and 16.
mohdashfan1999ashfan:
I did not understand
Answered by
22
Let common ratio be x
Therefore, 1 number = 2x, other = 3x.
9x²-4x²=320 {given}
x²=320/5
x²=64
Therefore, x= √64 = 8
Therefore, Numbers are :
16 and 24
Therefore, 1 number = 2x, other = 3x.
9x²-4x²=320 {given}
x²=320/5
x²=64
Therefore, x= √64 = 8
Therefore, Numbers are :
16 and 24
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