Two numbers are in the ratio 2:3. If 9 is added to
each they will be in the ratio 3:4, the numbers are
( 12,
28 (2) 18,27 (3) 8, 12 (4) 10, 15
Answers
- Two numbers are in the ratio 2:3
- If 9 is added to each they will be in the ratio 3:4
Let,
- First Number = x
- Second Number = y
A/C to question,
==> x : y = 2 :3
==> x/y = 2/3
==> 3x - 2y = 0 -------------(1)
Again,
==> (x+9) : (y+9) = 3:4
==> (x+9)/(y+9) = 3/4
==> 4x - 3y = 27 - 36
==> 4x - 3y = - 9------------(2)
Multiply by 4 in equ(1) & 3 in equ(2)
- 12x - 8y = 0
- 12x - 9y = -27
________________Sub. it's
==> -8y + 9y = 27
==> y = 27
keep value of y in equ(1)
==> 3x - 2*27 = 0
==> 3x = 54
==> x = 54/3
==> x = 18
- First Number be = 18
- Second Number be = 27
_________________
Answer:
(2) 18,27
The numbers are
First number = 18
Second number = 27
Step-by-step explanation:
Given:
• Two numbers are in the ratio 2:3
• If 9 is added to each they will be in the ratio = 3:4
Find :
• The two numbers
Solution :
Let,
First number = 2x
Second number = 3x
9 is added to each number
So,
First number = 2x + 9
Second number = 3x + 9
They will be in the ratio = 3:4
According to question :
⇒
⇒ 4 (2x + 9) = 3 (3x + 9)
⇒ 8x + 36 = 9x + 27
⇒ 8x - 9x = 27 - 36
⇒ - 1x = - 9
⇒ 1x = 9
⇒ x = 9
★ First number = 2x
⇒ 2 (9)
⇒ 2 × 9
⇒ 18
★ Second number = 3x
⇒ 3 (9)
⇒ 3 × 9
⇒ 27
Therefore,
First number = 18
Second number = 27