Two numbers are in the ratio 2:3. If the difference between them is 12, what percentage of the product of the two numbers is their sum?
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Step-by-step explanation:
thieir ratio = 2:3
difference = 12
3x - 2x = 12 => x = 12
sum = 5x = 5(12) = 60
product = 2x × 3x = 6x^2= 6(12)^2= 864
required% = 60/864 * 100 = 6.94%
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