Question

Two numbers are in the ratio 2:3 if their LCM is 48 what is the sum of the numbers? ​

Answer 1

Answer:

If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9. Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

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Solved Examples(Set 1) - HCF and LCM.

1. Two numbers are in the ratio 2 : 3. If their L.C.M. is 48. what is sum of the numbers?

A. 64 B. 42

C. 28 D. 40

Answer 2

Answer:

40

Step-by-step explanation:

2 x 3 = 6(let say)

then 6 == 48

1== 8

so sum will be...

2+3 =5

5 x 8 = 40