Question

Two numbers are in the ratio 2 : 5, their
LCM is 40. Find the smallest number?
[ ]
రెండు సంఖ్యల నిష్పత్తి 2 : 5, వాటి క.సా.గు. 40 అయితే
చిన్న సంఖ్యని కనుగొనండి.
(i)
10
(ii) 20
(iv) 4
(ⅱ) 8




what is the answer from this question?​

Answer 1

Answer:

so lets take the no. 2x and 5x

their lcm would be 10x

hence,

10x = 40

x =4

numbers = 2(4)

= 8

=5 (4)

= 20

smallest number is 8 (ii)

please matk brainliest and thank you ❤

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

Two numbers are in the ratio 2 : 5, their LCM is 40. The smallest number

(i) 10

(ii) 8

(iii) 20

(iv) 4

CONCEPT TO BE IMPLEMENTED

LCM :

For the given two or more numbers LCM is the least number which is exactly divisible by each of the given numbers

EVALUATION

Here it is given that two numbers are in the ratio 2 : 5

Let the two numbers are 2N and 5N

Then LCM = 2 × 5 × N = 10N

Their LCM is 40

So by the given condition

10N = 40

⇒ N = 4

So the numbers are

First number = 2N = 2 × 4 = 8

Second number = 5N = 5 × 4 = 20

Hence the smaller number = 8

FINAL ANSWER

Hence the correct option is (ii) 8

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