Question

Two numbers are in the ratio 3:2 If they differ by 18 , what are the numbers?​

Answer 1

Answer -

• The numbers are 54 and 36.

To find -

• The numbers.

Step-by-step explanation -

 

Let the numbers be "3x" and "2x", as they are in the ratio 3 : 2.  

According to the Question -

• 3x - 2x = 18.

On solving the equation -

$\longrightarrow$ 3x - 2x = 18  

$\longrightarrow$ x = 18

Hence, the numbers are -

$\longrightarrow$ 3x = 3 × 18 = 54.

$\longrightarrow$ 2x = 2 × 18 = 36.

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Verification -

• To check our answer, let's substitute the value of "x" in the equation and see whether LHS = RHS.  

LHS :

$\longrightarrow$ 3x - 2x

$\longrightarrow$ 3 × 18 - 2 × 18

$\longrightarrow$ 54 - 36

$\longrightarrow$ 18

RHS :

$\longrightarrow$ 18

LHS = RHS.

Hence verified!!

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Answer 2

Answer:

The required numbers are 54 and 36.

Step-by-step explanation:

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➜ Given:-

• Two numbers are in the ratio 3:2
• They differ by 18

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➜ To Find:-

• What are the numbers?

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➜ Calculation:-

• Let the required numbers be 3x and 2x

ACCORDING TO THE QUESTION

$\implies \: \sf \: 3x \: - \: 2x \: = \: 18 \\ \\ \sf \implies \: \boxed{ \sf \: x \: = \: 18} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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First Number = 3x = 3 × 18 = 54

Second Number = 2x = 2 × 18 = 36

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➼ Final Answer-:

The required numbers are 54 and 36.

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