Question

Two numbers are in the ratio 3: 4. If the sum of their cubes is 11375, then find the

smaller number​

Answer 1

Answer:

smaller number is 15

Step-by-step explanation:

let the numbers be 3x and 4x

according to the question,

$(3x)^3$+ $(4x)^3$ = 11375

$27x^3 + 64x^3 = 11375\\91 x^3 = 11375\\x^3 = (11375/91 ) = 125 \\x = \sqrt[3]{125} \\x = 5$

therefore required number are 3 × 5 , 4 × 5

                                                   = 15 , 20