Question

two numbers are in the ratio 3:4.the product of their HCF and LCM is 2028 the sum of the number is​

Answer 1

Step-by-step explanation:

let those two numbers be 3x , 4x .

product of two numbers=H.C.F × L.CM

12x^2 = 2028

x^2 = 169 => x = 13

sum of the numbers is

= 3x + 4x = 7x = 7(13) = 91 Ans.

Answer 2

Step-by-step explanation:

12 x^2 = 2028

x^2 = 169

x = 13

39 + 52 = 91