Question

Two numbers are in the ratio 3:4. The product of their hcf and lcm is 2028. The sum of the number will be

Answer 1

Two numbers Ratio=3:4
Let it be=3x & 4x
Product of HCF and LCM=2028

As we know

Product of two numbers=LCM× HCF
4x ×3x=2028
12x²=2028
x²=2028/12
x²=169
X=√169
X=13

1 st number=3x=3×13=39
2nd number=4x=4×13=52

Sum =39+52=91

Answer 2

Answer : 91

Step by Step explanation :

Given ratio = 3 : 4

Let the numbers be 3p , 4p.

Product of their HCF and LCM = 2028 .

We know the relation ,

Product of the numbers = Product of HCF & LCM.

So ,

3p ( 4p ) = 2028

12p² = 2028

p² = 169

p = 13 .

Therefore , The numbers are 3(13) , 4(13 )

= 39 , 52

Sum of the numbers = 39 + 52 = 91 .