Math, asked by raunaque38, 1 year ago

two numbers are in the ratio 3:5 and sum is 96 the larger number is

Answers

Answered by kshitij2211
52
3x+5x=96
8x=96
x=12

3x=>3×12=>36
5x=>5×12=>60

Hence larger number is 60
Answered by marishthangaraj
7

The larger number is 60

Given:

Two numbers are in the ratio 3:5

Sum of the two numbers is 96

To find:

The larger number.

Solution:

Step 1 of 2:

Two numbers are in the ratio 3:5

Let the two numbers be 'x' and 'y'

x:y = 3:5

\frac{x}{y} = \frac{3}{5}

x = \frac{3}{5}y

Sum of the two numbers is 96

x + y = 96

Step 2 of 2:

x + y = 96

x = \frac{3}{5}y

\frac{3y}{5} + y = 96

\frac{3y+5y}{5} = 96

8y = 96 × 5

8y = 480

y = \frac{480}{8}

y = 60

x = \frac{3}{5}(60)

x = 3 × 12

x = 36

Therefore,

The two numbers are 36 and 60

Hence, The larger number is 60

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