Question

Two numbers are in the ratio 3:5. If the numbers are increased by 10 their ratio will become 5:7. What are the original numbers.

Answer 1

$\bold{\boxed{HEY!!!}}$

$<b>{Here is your answer :- }$

Two numbers are in the ratio 3 : 5.

Let the common multiplayer be " x ".

So by the given condition

$\frac{3x + 10}{5x + 10} = \frac{5}{7} \\ \\ cross \: multiplying \\ \\ (3x + 10)7 = (5x + 10)5 \\ \\ 21x + 70 = 25x + 50 \\ \\ 25x - 21x = 70 - 50 \\ \\ 4x = 20 \\ \\ x = \frac{20}{4} \\ \\ x = 5$
So the numbers are 3x = 3 × 5 = 15

5x = 5 × 5 = 25

$\bold{\boxed{\:SO \:THE \:NUMBERS\: ARE\: 15\: & \:25 }}$

$<marquee>THANKS...$

Answer 2

Hey !!




Let the numbers are 3X and 5X.


According to the question,




( 3X + 10 / 5X + 10 ) = 5/7



7 ( 3X + 10 ) = 5 ( 5X + 10 )





21X + 70 = 25X + 50



25X - 21X = 70 - 50



4X = 20


X = 5.



First number = 3X = 3 × 5 = 15.


And,


Second number = 5X = 5 × 5 = 25.