Question

Two numbers are in the ratio 3:5. When each of these numbers is increased by 10, their ratio becomes 5:7. Find the greater number. Please no spam tomorrow is my exam​

Answer 1

Step-by-step explanation:

$\red{\textbf{Answer}}$ ➧ 25

Step-by-step explanation:

$\blue{\texttt{Given :-}}$

$\textsf{Two numbers are in the ratio 3:5}$

$\textsf{Let the first number is}$ $\blue{\texttt{x}}$

$\textsf{ the second number is}$ $\blue{\texttt{y}}$

$\textsf{then ,}$

$\Large\frac{x}{y} = \Large\frac{3}{5}$

$3y = 5x$

$\textsf{on the other hand,}$

$\Large\frac{x + 10}{y + 10} = \Large\frac{5}{7}$

$\textsf{hence,}$$7(x + 10) = 5(y + 10)$

$\textsf{we get that,}$

$3y = 5x$,$7x + 70 = 5y + 50$

$3y = 5x \: , 5y = 7x + 20$

$y = \Large\frac{5x}{3}$,$y = \Large\frac{7x + 20}{5}$

∴ $\Large\frac{5x}{3} = \Large\frac{7x + 20}{5}$

$25x = 3(7x + 20)$

$25x = 21x + 60$

$4x = 60$

∴ $x = 15$

$\textsf{then,}$

$y = \Large\frac{5x}{3} = 5 \times \Large\frac{15}{3}$ $= 25$

$\red{\textbf{x = 15 , y = 25}}$

$\blue{\texttt{The greater number is }}$ $\red{\textbf{25}}$

Answer 2

Answer:

Let the first number is x, the second is y.Then

y

x

=

5

3

, 3y=5x

On the other hand

y+10

x+10

=

7

5

,hence 7(x+10)=5(y+10)

We get that 3y=5x,7x+70=5y+50

3y=5x,5y=7x+20

y=

3

5x

,y=

5

7x+20

∴

3

5x

=

5

7x+20

25x=3(7x+20)

25x=21x+60

4x=60

∴ x=15

⇒ Then y=

3

5x

=5×

3

15

=25

∴ x=15,y=25

∴ The greater number is 25.