Question

two numbers are in the ratio 3:8if 20 is added to each of these their sum becomes 106 write the numbers ​

Answer 1

Step-by-step explanation:

(3x+20)+(8x+20)=106

11x+40=106

11x=106-40=66

x=66/11

x=6

3x=18

8x=48

Answer 2

Step-by-step explanation:

Let the two numbers be 3x and 8x

Now,

Add 20 to both numbers and their sum will be 106 (given)

Then,

(3x +20 ) + (8x +20 ) = 106

11x + 40 = 106

11x = 106 -40

11x = 66

x = 66 /11

x = 6

Now,

First no. 3x = 3×6

= 18

Second no. 8x = 8× 6

= 48

So the two numbers are 18 and 48

Thnx