Two numbers are in the ratio 4:5. If difference of their cube is 61, find the numbers.
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Answered by
265
Let the numbers be 4x and 5x.
As per given condition we have,
(5x)³-(4x)³=61
125x³-64x³=61
61x³=61
x³=61/61
x³=1
x=1
Now,
4x=4×1=4
5x=5×1=5
Hence required numbers are 4 and 5.
As per given condition we have,
(5x)³-(4x)³=61
125x³-64x³=61
61x³=61
x³=61/61
x³=1
x=1
Now,
4x=4×1=4
5x=5×1=5
Hence required numbers are 4 and 5.
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19
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