Question

two numbers are in the ratio 4:5 their sum is 6:3. find the number​

Answer 1

Appropriate Question:

Two numbers are in the ratio 4:5 their sum is 63. Find the numbers.

Answer:

28 & 35

Step-by-step explanation:

As per the provided information in the given question, we have :

• Two numbers are in the ratio of 4:5.
• The sum of two numbers is 63.

We've been asked to calculate the number.

In order to calculate the number firstly we need to frame a particular linear equation. By solving the equation further we can easily calculate the numbers.

As the numbers are in the ratio of 4:5. Let us suppose the numbers as 4x and 5x respectively. according to the question, the sum of the numbers is 63. Writing it in the form of a linear equation,

$\dashrightarrow \rm{\quad { 4x + 5x = 63}}$

Performing addition of the terms in the LHS.

$\dashrightarrow \rm{\quad { 9x = 63}}$

Now, transpose 9 from LHS to RHS. Note that, when the terms are transposed, their arithmetic operator get changed. Here, 9 is in the form of multiplication. In RHS, it'll become in the form of division.

$\dashrightarrow \rm{\quad { x =\cancel{\dfrac{ 63}{9}}}}$

Cancelling the terms.

$\dashrightarrow \quad \underline{\boxed{ \bf x = 7}}$

⠀⠀⠀___________________________⠀⠀⠀⠀⠀⠀

• First number = 4(x) = 4(7) = 28
• Second number = 5(x) = 5(7) = 35

Therefore, the required numbers are 28 and 35.

Answer 2

$\huge\purple{ \underline{ \boxed{\mathbb\colorbox{cyan}{\red{QUESTION : }}}}}$

Two numbers are in the ratio 4 : 5 . Their sum is 63. Find the number .

$\huge\purple{ \underline{ \boxed{\mathbb\colorbox{cyan}{\red{ANSWER : }}}}}$

Two numbers are 28 and 35 .

$\huge\purple{ \underline{ \boxed{\mathbb\colorbox{cyan}{\red{EXPLANATION : }}}}}$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

• Two numbers are in the ratio 4 : 5 .
• Their sum is 63.

$\green{ \large \underline{ \mathbb{\underline{TO \: FIND : }}}}$

• Two numbers .

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

Let numbers as 4x and 5x .

Therefore

According to question : -

$\sf \implies4x + 5x = 63 \\ \\\sf \implies9x = 63 \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies x = \cancel \frac{63}{9} \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies x = 7 \: \: \: \: \: \: \: \: \: \: \:$

First number = 4x = 4(7) = 28

Second number = 5x = 5(7) = 35