Question

two numbers are in the ratio 4:5 when 6 is added to each number the ratio becomes 9:11 find the numbers

Answer 1

Answer:

hi

Step-by-step explanation:

leta/b=4/5 call this #1; then

(a+6)/(b+6)=13/16 call this #2

from #1 a/b=4/5 multiply each side by b

a=4b/5 now substitute into #2 we get:

(4b/5+6)/(b+6)=13/16

{(4b+30)/5}/(b+6)=13/16 multiply both sides by 5

(4b+30)/b+6)=13x5/16=65/16 multiply each side by 16

16(4b+30)/(b+6)=65

(64b+480)/(b+6)=65 multiply each side by (b+6)

64b+480= 65(b+6)

64b+480= 65b+390 now subtract 64b+390 from each side

90= b

since a=4b/5 =4x90/5 =72