two numbers are in the ratio 4:7.if 4 is subtracted from each of the number,then the ratio becomes 7:13 find the number
Answers
Answer:
One number = 33
Another number = 56
Step-by-step explanation:
given that,
wo numbers are in the ratio 4:7
let the common ratio be x
so,
one number will 4x
and another number will 7x
also given that,
4:7.if 4 is subtracted from each of the number,then the ratio becomes 7:13
so,
According to the question
(4x - 4)/(7x - 4) = 7/13
by solving the equation
13(4x - 4) = 7(7x - 4)
52x - 52 = 49x - 28
52x - 49x = -28 + 52
3x = 24
x = 24/3
x = 8
so,
we have the common ratio of the two numbers = 8
given numbers = 4x
= 4(8)
= 32
another number = 7x
= 7(8)
= 56
so,
One number = 33
Another number = 56
Answer:
Required numbers = 32 and 56
Step-by-step explanation:
given
numbers are in the ratio 4:7
let the common ratio be x
so,
so numbers will 4x and 7x
ATQ,
(4x - 4)/(7x - 4) = 7/13
13(4x - 4) = 7(7x - 4)
52x - 52 = 49x - 28
52x - 49x = -28 + 52
3x = 24
x = 24/3
x = 8
so,
numbers = 4x
= 4(8)
= 32
another number = 7x
= 7(8)
= 56
so,