Question

two numbers are in the ratio 4:7.if 4 is subtracted from each of the number,then the ratio becomes 7:13 find the number​

Answer 1

Answer:

One number = 33

Another number = 56

Step-by-step explanation:

given that,

wo numbers are in the ratio 4:7

let the common ratio be x

so,

one number will 4x

and another number will 7x

also given that,

4:7.if 4 is subtracted from each of the number,then the ratio becomes 7:13

so,

According to the question

(4x - 4)/(7x - 4) = 7/13

by solving the equation

13(4x - 4) = 7(7x - 4)

52x - 52 = 49x - 28

52x - 49x = -28 + 52

3x = 24

x = 24/3

x = 8

so,

we have the common ratio of the two numbers = 8

given numbers = 4x

= 4(8)

= 32

another number = 7x

= 7(8)

= 56

so,

One number = 33

Another number = 56

Answer 2

Answer:

Required numbers = 32 and 56

Step-by-step explanation:

given

numbers are in the ratio 4:7

let the common ratio be x

so,

so numbers will 4x and 7x

ATQ,

(4x - 4)/(7x - 4) = 7/13

13(4x - 4) = 7(7x - 4)

52x - 52 = 49x - 28

52x - 49x = -28 + 52

3x = 24

x = 24/3

x = 8

so,

numbers = 4x

= 4(8)

= 32

another number = 7x

= 7(8)

= 56

so,

Required numbers = 32 and 56