two numbers are in the ratio 4:7.the difference of their squares is 297.find the numbers
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let the numbers be 4x and 7x.
(7x)^2 - (4x)^2 = 297
49x^2 - 16x^2 = 297
33x^2 = 297
x^2 = 297/33 = 9
x = 3
first number would be 12
and second number would be 21.
(7x)^2 - (4x)^2 = 297
49x^2 - 16x^2 = 297
33x^2 = 297
x^2 = 297/33 = 9
x = 3
first number would be 12
and second number would be 21.
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