Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:
(A) 40, 42
(B) 42, 48
(C) 40, 48
(D) 44, 50
Answers
Answered by
16
Answer: (C) 40,48
Explanation:
According to given information
x/y=5/6
=> 6x-5y=0 ........(I)
x-8/y-8=4/5
=> 5x-40=4y-32
=> 5x-4y=8 ...........(II)
from eq. (I)
6x-5y=0
=> x=5y/6
substituting in......(II)
5x-4y=8
=>5[5y/6]-4y=8
=>y/6=8
=>y=48
THEREFORE
x=5y/6
=>x=5×48/6
=> x=40
Answered by
0
Answer:
Step-by-step explanation:
let the two no be x and y
therefore x / y = 5 / 6
6 * x = 5 * y
6 * x - 5 * y = 0 * 5
30 * x - 25 * y = 0 ..................(i)
also (x - 8)/(y - 8) = 4 / 5
5 * x - 40 = 4 * y - 32
5 * x - 4 * y - 8 = 0 *6
30 * x - 24 * y - 48 = 0 .....................(ii)
subtracting (i) from (ii)
y - 48 = 0
y = 48
putting y = 48 in x/y = 5/6
x/48 = 5/6
x = 5 * 48 / 6
x = 5 * 8
x = 40
therefore the two numbers are 40 and 48
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