Question

Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:

(A) 40, 42                                           

(B) 42, 48

(C) 40, 48                                           

(D) 44, 50


​

Answer 1

Answer: (C) 40,48

Explanation:

According to given information

x/y=5/6

=> 6x-5y=0 ........(I)

x-8/y-8=4/5

=> 5x-40=4y-32

=> 5x-4y=8 ...........(II)

from eq. (I)

6x-5y=0

=> x=5y/6

substituting in......(II)

5x-4y=8

=>5[5y/6]-4y=8

=>y/6=8

=>y=48

THEREFORE

x=5y/6

=>x=5×48/6

=> x=40

Answer 2

Answer:

Step-by-step explanation:

let the two no be x and y

therefore x / y = 5 / 6

6 * x = 5 * y

6 * x - 5 * y = 0             * 5

    30 * x -     25 * y = 0 ..................(i)

also (x - 8)/(y - 8) = 4 / 5

5 * x - 40 = 4 * y - 32

5 * x - 4 * y - 8 = 0                 *6

30 * x - 24 * y - 48 = 0 .....................(ii)

subtracting  (i) from (ii)

y - 48 = 0

y = 48

putting y = 48 in x/y = 5/6

x/48 = 5/6

x = 5 * 48 / 6

x = 5 * 8

x = 40

therefore the two numbers are 40 and 48