Question

Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:

(A) 40, 42                                           

(B) 42, 48

(C) 40, 48                                           

(D) 44, 50


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Answer 1

x/y = 5/6

x × 6 = y × 5

6x – 5y = 0………………..(1)

If 8 is subtracted from each of the numbers then the ratio is 4:5.

x−8y−8=45

Then the equation is

5x – 4y = 8……………….(2)

From equation (1)

x = 5y/6

Substituting value of x in equation (2)

5(5y/6) – 4y = 8

y = 48

Substitute the value of y in equation (1) we get

6x – 5(48) = 0

6x = 240

x = 40

Therefore the numbers are 40 and 48.

Answer 2

ANSWER

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

hope it's helps you ❤️