Question

Two numbers are in the ratio 5:6 , Of 8 is substracted from each, the ratio becomes 4:5, Find the numbers​

Answer 1

Step-by-step explanation:

⭐ Let the required numbers be 5x and 6x . Then ,

$\large{\sf {\frac{5x-8}{6x-8}}}$

$\large{\sf {\frac{4}{5}}}$

$\large\implies{\sf }$ 5(5x-8) =4(6x-8)

$\large\implies{\sf }$ 25x-40 = 24x-32

$\large\implies{\sf }$ 25x-24x =40-32

$\large\implies{\sf }$ X= 8

__________________________

⭐Hence, the required

numbers are (5 X 8)=40 and (6 x 8)= 48

Answer 2

AnswEr :

• Two No(s). in Ratio 5 : 6
• 8 is subtracted from both and then the ratio will be 4 : 5.
• Find the Numbers.

Let the Numbers be 5a and, 6a.

• According to the Question Now :

⇒ Original Numbers - 8 = New Ratio

⇒ (5a - 8) : (6a - 8) = 4 : 5

• Product of Mean = Product of Extreme

⇒ (5a - 8) × 5 = 4 × (6a - 8)

⇒ 25a - 40 = 24a - 32

⇒ 25a - 24a = 40 - 32

⇒ a = 8

◗ First No. = 5a = (5 × 8) = 40

◗ Second No. = 6a = (6 × 8) = 48

∴ Therefore, Numbers are 40 and 48.

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• Shortcut Trick to Solve Question :

⋆ Original No.⠀⠀– 8⠀⠀⠀⠀⋆ New No.

First : Second⠀⠀⠀⠀⠀⠀⠀⠀⠀First : Second

⠀⠀5 : 6⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀4 : 5

Difference of both Ratios is (6 - 5) = 1 and, (5 - 4) = 1, Here the Difference is Same or else we will have to Multiply them by Opposite terms to make same Difference.

So, we will find the Difference of Ratio in No(s)., that Means we can find from like First No. (5 - 4) = 1 or, Second No. (6 - 4) = 1

Divide Number Gap By that Number.

↦ Number Gap / Difference of No.

↦ 8 / 1

↦ 8

Now, Just Multiply the Outcome (8 in this Case) with any of the Ratio of find Number. Here we have to Find Original Numbers :

◗ First No. = 5a = (5 × 8) = 40

◗ Second No. = 6a = (6 × 8) = 48

∴ Therefore, Numbers are 40 and 48.