Question

Two numbers are in the ratio 5:7. if 12 is subtracted from each number, the new
numbers will be in the ratio 7: 11. Find the original numbers​

Answer 1

Answer:

The original no. are 40 and 56.

Answer 2

Step-by-step explanation:

Let the numbers be 5x and 7x.

ATQ,

$\tt \implies \dfrac{5x-12}{7x-12}= \dfrac{7}{11}$

Now,

$\tt\implies 11(5x-12) = 7(7x-12)$

$\tt \implies 55x-132 = 49x-84$

$\tt\implies 55x-49x =132-84$

$\tt \implies 6x=48$

$\tt \implies x = \dfrac{\cancel{48}}{\cancel{6}}$

$\tt \implies x = 8$

Original Numbers,

5x=5(8)=40

7x=7(8)=56

Hope it helps.