Question

TWO NUMBERS ARE IN THE RATIO 5:7.IF THEY DIFFER BY 42,FIND THE NUMBER​

Answer 1

Answer:

147,105

Step-by-step explanation:

let the numbers be 5y and 7y

According To Question:

7y -5y = 42

2y = 42

y = 42÷2

y = 21

The numbers are:

5y = 5×21 = 105

7y = 7×21 = 147

Answer 2

Hmmm... ITS EASY BRO...

LET THE TWO NUMBERS BE 5X AND 7X..

AS WE DONT KNOW THE REAL NUMBER SO WE HAVE SUPPOSED IT AS 5X AND 7X

AND NOW...

AS THEIR DIFF IS 42...

LETS DO CALCULATION..

AS ..

7X-5X=42...

WE GET .. 2X=42....

NOW...X=21....

AS X=21...

AND NOW 2X= 2x 21= 42....

and 7x= 7x 21 =147...

Hope you have got it.....