Question

two numbers are in the ratio 7:11 if 7 are added to each of the number the ratio becomes 2:3 find the numbers​

Answer 1

Step-by-step explanation:

Given

′

2

′

no's are in the ratio 7:11

′

7

′

is added to these no's then the ratio 2:3

Let 1st no= 7x

2nd no= 11x

11x+7

7x+7

=

3

2

3(7x+7)=2(11x+7)

21x+21=22x+14

22x−21x=21−14

x=7

1st no =7×7=49

2nd no =11×7=77

Answer 2

Answer:

1st no =7×7=49

2nd no =11×7=77

Step-by-step explanation:

Given two no's are in the ratio 7:11

7 is added to these no's then the ratio 2:3

Let 1st no= 7x

2nd no= 11x

7x+7 / 11x + 7 = 2/3

=>3(7x+7)=2(11x+7)

=>21x+21=22x+14

=>22x−21x=21−14

=>x=7

1st no =7×7=49

2nd no =11×7=77

hope it helps you

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