Math, asked by dude7014, 5 months ago

Two numbers are in the ratio 7:11. If 7 is added to each of the numbers, the ratio becomes 2:3. Find the number.

Answers

Answered by lokeshdusane5
1

Answer:

49 and 77

Step-by-step explanation:

The two number are in ratio 7:11

Let the ratio be x

So, Numbers are 7x and 11 x

Now 7 is added to both the ratio becomes 2:3

So, ATQ

\frac{7x+7}{11x+7}=\frac{2}{3}

11x+7

7x+7

=

3

2

3(7x+7)=2(11x+7)3(7x+7)=2(11x+7)

21x+21=22x+1421x+21=22x+14

7=x7=x

So, Numbers = 7 x = 7 * 7 = 49 , 11x = 11*7 = 77

Hence the numbers are 49 and 77

Answered by Anonymous
76

Answer :-

49 and 77.

Explanation :-

Given :-

  • Two numbers are in the ratio 7:11.

  • If 7 is added to each of the numbers, the ratio becomes 2:3.

To Find :-

  • Both the numbers.

Solution :-

Let,

  • First Number = 7x.
  • Second Number = 11x.

According to the Question,

➙ (7x + 7)/(11x + 7) = 2/3.

➙ 3(7x + 7) = 2(11x + 7).

➙ 21x + 21 = 22x + 14.

➙ 21x - 22x = 14 - 21

➙ -x = -7.

x = 7.

Therefore,

  • First Number = 7x = 49.
  • Second Number = 11x = 77.

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