Question

two Numbers are in the ratio 7:11. if 7 is added to each of the numbers the ratio becomes 2:3 find the numbers

Answer 1

7x+7/11x+7=2/3
3(7x+7)=2(11x+7)
x=7
therefore first number is 7×7=49
second number is =11×7= 77

Answer 2

Answer:

49 and 77

Step-by-step explanation:

The two number are in ratio  7:11

Let the ratio be x

So, Numbers are 7x and 11 x

Now 7 is added to both  the ratio becomes 2:3

So, ATQ

$\frac{7x+7}{11x+7}=\frac{2}{3}$

$3(7x+7)=2(11x+7)$

$21x+21=22x+14$

$7=x$

So, Numbers = 7 x = 7 * 7 = 49 , 11x = 11*7 = 77

Hence the numbers are 49 and 77