Question

two numbers are in the ratio 7:12 when 7 is added to both the ratio between them becomes 7: 11.Find the smallest of them​

Answer 1

Answer:

28

Step-by-step explanation:

given that ratio of two numbers = 7:12

let the common factor of both numbers be x

so,

numbers = 7x and 12x

ATQ,

$\large{ \frac{ \large{7x + 7}}{ \large{12x + 7}} = \frac{ \large{7}}{ \large{11}} }$

84x + 49 = 77x + 77

84x - 77x = 77 - 49

7x = 28

x = 28/7

x = 4

numbers = 7x and 12x

= 7 × 4 = 28

12x = 12 × 4 = 48

so,

numbers are 28 and 48

smallest number = 28

Answer 2

Answer:

take 1st number 7x

2nd number 12x

7x/12x +7/7= 7/11

find x