Question

Two numbers are in the ratio 7:5 . If they differ by 16. Find the smallest one​

Answer 1

Answer:

The smaller number is 40.

Step-by-step explanation:

let the numbers be 7x and 5x.

A/c,

7x - 5x = 16

2x = 16

x = 16/2

x = 8

The two numbers are :

7x = 7*8 = 56

5x = 5*8 = 40

The smaller number is 40.

Answer 2

Answer:

40

PLEASE MARK AS BRAINLIEST

Step-by-step explanation:

Let's say that the numbers are =x,y

x/y=7/5

with the help of cross multiplication =

7y=5x

Now we can find y in terms of x

=>y=5/7x

we know that

=> x-y=16

and we can replace y with its new value

=>x-5/7x=16

=>(7-5)/7x=16

=>2/7x=16

take 2/7 to 16 side

x=16x7/2

2 x 8=16

=>x=7 x 8=56

the smallest number =y

y=5/7x56

7 x 8=56

y= 5 x 8=40