Math, asked by kaylahross, 8 months ago

Two numbers are in the ratio 7:5. If they differ by 18, find the numbers.( show the steps)

Answers

Answered by tannigang
2

Step-by-step explanation:

Setting up two equations to solve for 2 unknowns. Let A = one number and B=the other number: First equation:

A/B=7/5 Multiply by B

A = 7B/5 Multiply by 5

5A = 7B or

5A - 7B = 0 Set up second equation:

A - B = 16 Multiply by 5:

5A - 5B = 80 Subtract the first equation from this equation:

5A - 7B = 0 5A-5A leaves nothing. -5B - (-7B) = 2B To subtract, reverse the sign and add.:

2B = 80 Solve:

B = 40 Substitute 40 for B in first equation:

A - 40 = 16 Solve:

A = 56 The two numbers are 56 and 40. To check divide by 8. 56/8 = 7 and 40/8 = 5. So the ratio between the numbers is 7/5 and difference is 16 CHECK!

Or you can use 1 equation to get to the answer:

7x-5x=16 solve

2x=16

x=8 substitute 8 into the equation:

7 times 8 is 56. 5 times 8 is 40

56–40 is 16 The two numbers are 56 and 40.

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Answered by debanjankrishna
1

Step-by-step explanation:

given the ratio

7:5 then if I multiply a then its 7a:5a=7:5(same)

now ATQ

7a-5a=18

now solve the equation

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