two numbers are in the ratio 7:5.if they differ by 18,what are the numbers
Answers
Answered by
4
let the two no. be 7x and 5x
7x-5x=18
2x=18
x=9
therefore the no. are
63 and 45
7x-5x=18
2x=18
x=9
therefore the no. are
63 and 45
arnavpandita1:
please mark me brainliest
Answered by
0
let x and y are these two numbers ,
according to question ,
x : y = 7: 5
x / y = 7/ 5 ------eq.(1)
x - y = 18
x = 18 + y -------- eq.(2)
put value of " x" in (1) , we get
18 + y / y = 7 / 5
5 ( 18 + y) = 7y
90 + 5y = 7y
2y = 90
y = 45
now put value of " y " in eq.(2)
x = 18 + 45 = 63
hence , the two numbers are 63 and 45 .
【 hope it helps 】
according to question ,
x : y = 7: 5
x / y = 7/ 5 ------eq.(1)
x - y = 18
x = 18 + y -------- eq.(2)
put value of " x" in (1) , we get
18 + y / y = 7 / 5
5 ( 18 + y) = 7y
90 + 5y = 7y
2y = 90
y = 45
now put value of " y " in eq.(2)
x = 18 + 45 = 63
hence , the two numbers are 63 and 45 .
【 hope it helps 】
Similar questions