two numbers are in the ratio 8:3. if the sum of the mumbers is 143, find the numbers.
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Answered by
4
let the numbers be x and y
x/y = 8/3
3x = 8y
x+y = 143
3x + 3y = 429
8y+3y = 429
11y = 429
y = 39
x = 143 - 39 = 104
x/y = 8/3
3x = 8y
x+y = 143
3x + 3y = 429
8y+3y = 429
11y = 429
y = 39
x = 143 - 39 = 104
Answered by
2
Hey !!
Here is your answer.. ⬇⬇
Let the number be x.
Given that ratio of two number is 8:3.
one no. = 8x
another no. = 3x
Given the sum of the numbers is 143.
8x + 3x = 143
11x = 143
x = 143/11
x = 13
One no. = 8x = 8 ( 13 ) = 104
another no. = 3x = 3 ( 13 ) = 39
HOPE IT HELPS...
THANKS ^-^
Here is your answer.. ⬇⬇
Let the number be x.
Given that ratio of two number is 8:3.
one no. = 8x
another no. = 3x
Given the sum of the numbers is 143.
8x + 3x = 143
11x = 143
x = 143/11
x = 13
One no. = 8x = 8 ( 13 ) = 104
another no. = 3x = 3 ( 13 ) = 39
HOPE IT HELPS...
THANKS ^-^
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