Two numbers are in the ratio 8 : 3. If the sum of the numbers is 143, find the numbers.
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8 by 3 multiple by 13 then substracting it with 143
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Answer:
▪︎Let the first number be 8x and second number be 3x simultaneously. As 8:3 of both digits are given to us.
So ATQ,
8x + 3x = 143
11x = 143
x = 143/11
{ x = 13 }
Now, first number will be = 8x = 8 × 13 = 104
and second number will be = 3 × 13 = 39
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