Math, asked by rocky0000141, 7 months ago

Two numbers are in the ratio of
2:3 , if sum of their squares is 468,find them.​

Answers

Answered by Anonymous
12

Answer:

Let one number be 2x and other be 3x

Then,

(2x)² + (3x)² = 468

4x² + 9x² = 468

13x² = 468

x² = 36

x = 6

Hope it will be helpful :)☺️

Answered by Anonymous
2

\underline{\underline{\mathit{\huge{\purple{ AnSwEr }}}}}

\implies

.....

 \frac{x}{y}  =  \frac{2}{3} \\  3x = 2y

eq.......(1)

x = \frac{2y}{3}

for

 {x}^{2}

 {x}^{2}  =  \frac{4 {y}^{2} }{9}

A/Q,

 {x}^{2}  +  {y}^{2}  = 468

 \frac{4 {y}^{2} }{9}  +  {y}^{2}  = 468 \\  \frac{4 {y}^{2} + 9 {y}^{2}  }{9}  = 468 \\ 13 {y}^{2}  = 468 \times 9 \\ 13 {y}^{2}  = 4212 \\  {y}^{2}  =  \frac{4212}{13}  \\  {y}^{2}  = 324 \\ y =  \sqrt{324}  \\ y = 18

for the value of x...putting the value of y

x =  \frac{2y}{3}  \\ x =  \frac{2 \times 18}{3}  \\ x = 6 \times 2 \\ x = 12

<body bgcolor = "Lavender">

\mathfrak{\red{\huge{\underline{\overline{ ♡Good  }}}}} \mathfrak{\huge{\underline{\overline{\red{ Morning♡ }}}}}<marquee direction = "left"  bgcolor = "aqua"> Hope this helps uh☺️❤️✌️

Similar questions