Question

Two numbers are in the ratio of 2:3.If their product is 600,find the numbers.

Answer 1

Answer:

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Answer 2

Answer:

Let the two numbers be 2x and 3x

A/q,

2x × 3x = 600

6x² = 600

x² =600/6

x² = 100

x = ±100

x = ±10

∴ 1st number = 2x = 2 × 10 = ±20

∴ 2nd number = 3x = 3 × 10 = ±30

[Note :- ± This sign means, the number may be negative or positive.]

Step-by-step explanation:

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