Math, asked by vijjumallavarapu, 1 month ago

Two numbers are in the ratio of 3:4, the product of their HCF and LCM is 2008. The sum
of the number is?​

Answers

Answered by laxmiverma20069
0

Answer:

91

Step-by-step explanation:

Given :The two numbers are in the ratio 3:4 the product of their hcf and lcm is 2028

To Find : the sum of the numbers is?

Solution:

The two numbers are in the ratio 3:4

Let the ratio be x

So, the numbers are 3 x and 4 x

The product of their hcf and lcm is 2028

HCF \times LCM = \text{Product of two numbers}HCF×LCM=Product of two numbers

2028 =3x \times 4x2028=3x×4x

2028 =12x^22028=12x

2

\frac{2028}{12} =x^2

12

2028

=x

2

169=x^2169=x

2

\sqrt{169}=x

169

=x

13=x13=x

So, numbers are 3x = 3\times 13 = 393x=3×13=39 and 4x = 4\times 13 = 524x=4×13=52

Sum of numbers = 39+52= 91

Hence the sum of the numbers is 91.

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