Question

two numbers are in the ratio of 3:5. if 10 is added to both the numbers new ratio becomes 5:7 find both numbers​

Answer 1

Step-by-step explanation:

let number be 3x and 5x

3x + 10/5x +10 = 5/7

21x +70 = 25x + 50

21x- 25x = 50 - 70

4x = 20

x= 5

number are 3x = 3× 5 = 15

5x = 5×5 = 25

Answer 2

Answer:

Given :-

• The numbers are in the ratio of 3 : 5. If 10 is added to both the numbers then new ratio becomes 5 : 7.

To Find :-

• What are the numbers.

Solution :-

Let, the first number be 3x

And, the second number will be 5x

According to the question,

⇒ $\sf\dfrac{3x + 10}{5x + 10} =\: \dfrac{5}{7}$

By doing cross multiplication we get,

⇒ $\sf 5(5x + 10) =\: 7(3x + 10)$

⇒ $\sf 25x + 50 =\: 21x + 70$

⇒ $\sf 25x - 21x =\: 70 - 50$

⇒ $\sf 4x =\: 20$

⇒ $\sf x =\: \dfrac{\cancel{20}}{\cancel{4}}$

➠ $\sf\red{x =\: 5}$

Hence, the required numbers are,

✧ First number = 3x = 3(5) = 15

✧ Second number = 5(5) = 25

$\therefore$ The numbers are 15 and 25.