Question

Two numbers are in the ratio of 4:3,.If they differ by 18 , find these numbers​

Answer 1

Answer:

Le the numbers be 4x and 3x

ATQ,

The two numbers are differ by 18

So,

4x - 3x = 18

=> x = 18

4x = 4* 18 = 72

3x = 3 * 18 = 54

Therefore the two numbers are 72 and 54

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Answer 2

${\underline{\sf{Question}}}$

Two numbers are in the ratio of 4:3.If they differ by 18 , find these numbers.

${\underline{\sf{Solution}}}$

Let the two numbers be 4x and 3x

According to the question:

Numbers differ by 18

$\sf \implies \: 4x - 3x = 18$

$\sf \implies \: x = 18$

Thus, One number = 4x = 4×18 = 72

and other number = 3x = 3× 18= 54

Therefore,two numbers are 72 and 54 .

$\rule{200}2$

${\red{\underline{\underline{\bold{Verification}}}}}$

• Numbers differ by 18

$\sf \implies72 - 54 = 18$

• Numbers are in the ratio of 4:3

$\sf \implies \dfrac{72}{54} = \dfrac{4}{3}$

Hence verified !