Two numbers are in the ratio of 5 : 7. If 3 is subtracted from each of them, the ratio becomes 2 : 3 .Find the numbers.
Answers
Answer:
I hope that this is your answer the question
Step-by-step explanation:
The numbers are in the ratio 5:7
Let their common multiple be 'x'
The numbers are 5x, 7x
If 3 is subtracted from each of them the ratio becomes 2:3
5x-3/7x-3 = 2/3
3(5x-3) = 2(7x-3) (cross multiplication)
15x -9 = 14x -6
15x-14x = -6+9
x=+3
Therefore the numbers are 5* 3 =15, 7*3 = 21
(Verifications when 3 is subtracted from each other ,the ratio is 2/3, 15–3/21–3 = 12/18 = 2/3 ) verified)
The numbers are 15 & 21.
Let the numbers be 5x and 7x.
(5x-3):(7x-3)::2:3, or
2(7x-3) = 3(5x-3), or
14x-6 = 15x-9, or
15–14x=9–6, or x = 3.
Answer:
I hope that this is your answer the question
Step-by-step explanation:
The numbers are in the ratio 5:7
Let their common multiple be 'x'
The numbers are 5x, 7x
If 3 is subtracted from each of them the ratio becomes 2:3
5x-3/7x-3 = 2/3
3(5x-3) = 2(7x-3) (cross multiplication)
15x -9 = 14x -6
15x-14x = -6+9
x=+3
Therefore the numbers are 5* 3 =15, 7*3 = 21
(Verifications when 3 is subtracted from each other ,the ratio is 2/3, 15–3/21–3 = 12/18 = 2/3 ) verified)
The numbers are 15 & 21.
Let the numbers be 5x and 7x.
(5x-3):(7x-3)::2:3, or
2(7x-3) = 3(5x-3), or
14x-6 = 15x-9, or
15–14x=9–6, or x = 3.
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