Two numbers are in the ratio of 5:7. If the differs from 8 then the smallest number is
Answers
Answer:
smallest number among the 2 is 20
Step-by-step explanation:
Given- ratio of two numbers = 5:7
They differ by 8
To find- the smallest number
Solution-
Lets assume the first number as 5x
Lets assume the second number as 7x
therefore,
5x + 8 = 7x (as they differ by 8)
8 = 7x - 5x
8 = 2x
8/2 = x
x = 4
so, the first number= 5x
= 5(4)
= 20
second number = 7x
= 7(4)
= 28
Therefore the smallest number among the two numbers is 20
let the numbers are , 5x ; 7x
according to the question they differ by 8
Case I :
∴ 7x - 5x = 8
2x = 8
x = 4
hence the number are
7x = 7 × 4 = 28
5x = 5 × 4 = 20
hence , the smallest number is 20
Case II :
∴ 5x - 7x = 8
-2x = 8
x = -4
hence the number are
7x = 7 × -4 = -28
5x = 5 × -4 = -20
hence the smallest number is , -28