Question

two numbers are in the ratio of 7:4.if they differ by 21.what are the numbers..

Answer 1

Hello dear...here is your answer

ratio of the numbers.... 7:4

let the numbers are 7x and 4x

acc to question..

7x-4x=21

3x=21

x=7

so the numbers are 7×7=49

4×7=28

so the numbers are 49 and 28

hope it helps..... mark as brainliest

Answer 2

Answer:

49 and 28.

Step-by-step explanation:

Given:- Two numbers are in the ratio 7 : 4.

             Difference between the two numbers must be = 21.

To Find:- The two numbers that satisfies the above statement.

Solution:-

Let the numbers be 7x and 4x.

According to the question, difference between the numbers = 21

So we can write that

7x - 4x = 21

⇒ 3x = 21

⇒ x = 21 ÷ 3

⇒ x = 7

The numbers are 7x = 7 × 7 = 49 and 4x = 4 × 7 = 28.

Therefore, the two numbers in the ratio 7:4 whose difference is 21 are 49 and 28.

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