Question

Two numbers are in the ratio of 8 2 7. then 40 is added to the first number and 20 is subtracted from the second number to make the new ratio of the numbers 4 : 1. The larger of the two numbers initially was:

Answer 1

The answer is 48.

Hope it helps.

Answer 2

Answer:

48

Step-by-step explanation:

we are given that the two numbers are in ratio 8:7

Let the ratio be x

So, Numbers are 8x and 7x

Now we are given that  40 is added to the first number and 20 is subtracted from the second number to make the new ratio of the numbers 4 : 1.

So, $\frac{8x+40}{7x-20}=\frac{4}{1}$

$8x+40=28x-80$

$80+40=28x-8x$

$120=20x$

$x=6$

So, Numbers are $8x = 8 \times 6= 48$ and $7x= 7 \times 6 = 42$

Hence The larger of the two numbers initially was 48