Question

Two numbers are in the ration 4:3 .If they differ by 18, find these numbers.
​

Answer 1

$\huge \underline\mathfrak \color{aqua}❥ Answer ࿐$

$\longrightarrow\large { \boxed{\mathfrak \color{yellow}{54 \: and \: 72}}}$

$\huge \underline\mathfrak \color{deeppink}❥ Explanation ࿐$

☆To find:-

The numbers

☆Given :-

Two numbers are in the ratio 4:3 .

They differ by 18.

☆Assuming:-

Let the two numbers be 4x and 3x

☆Solution:-.

ATQ

$\leadsto \: 4x - 3x = 18 \\ \\ \rightarrow \color{red} x = 18 \qquad \: \: \: \:$

$\therefore \sf \: One \: number \: = 4x = 4 \times 18 = \color{lightgreen} \mathfrak72$

$\therefore \sf \: Other \: no\: = 3x = 3 \times 18 = \color{violet} \mathfrak54$

☆Hence:-

The two numbers are 72 and 54

hope it helps... :)

Answer 2

Answer:

Here is your answer :--

Le the numbers be 4x and 3x

ATQ,

The two numbers are differ by 18

So,

4x - 3x = 18

=> x = 18

4x = 4* 18 = 72

3x = 3 * 18 = 54

Therefore the two numbers are 72 and 54