Math, asked by bhawanagupta654, 6 months ago

Two numbers are less than a third number by 25 and 36 respectively. What is the percentage of first number less than the second number ?

Answers

Answered by rajutusharengineerin
2

Answer:

Step-by-step explanation: Required percentage =770×100=10%

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Answered by RvChaudharY50
0

Correct Question :- Two numbers are less than a third number by 25% and 36% respectively. What is the percentage of second number less than the first number ?

Solution :-

Let us assume that, the third number is equal to 100x .

So,

→ First number = 25% less than 100x = (100% - 25%) of 100x = 75% of 100x = (75 × 100x)/100 = 75x

and,

→ Second number = 36% less than 100x = (100% - 36%) of 100x = 64% of 100x = (64 × 100x)/100 = 64x

then,

→ Second number less than the first number by = 75x - 64x = 11x

therefore,

→ Required % = (Difference × 100) / First number

→ Required % = (11x × 100) / 75x

→ Required % = (44/3)%

→ Required % = 14(2/3)% (Ans.)

Hence, second number less than the first number by 14(2/3)% .

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