Question

Two numbers are less than a third number by 40% and 47% respectively. How much per cent is the second number less than the first ?(approx)

Answer 1

Answer:

Step-by-step explanation:

let the 3rd number be 100

therefore 1st number is 60

second number is53

required % = (7/70)*100

Helps you

Answer 2

Answer:

By 11%, the second number less than the first number.

Step-by-step explanation:

Step 1 of 2

Let the third number be $x$.

According to the question,

Two numbers are less than $a$ third number by 40% and 47%.

Then,

The first number is less than a third number by 40% is,

= $x-x\times 40\%$

= $x-x\times \frac{40}{100}$

= $\frac{100x-40x}{100}$

= $\frac{60x}{100}$

Similarly,

The second number is less than a third number by 47% is,

= $x-x\times 47\%$

= $x-x\times \frac{47}{100}$

= $\frac{100x-47x}{100}$

= $\frac{53x}{100}$

Step 2 of 2

Calculate the percent of second number less than the first.

Decrease in number = first number - second number

                                  = $\frac{60x}{100}-\frac{53x}{100}$

                                  = $\frac{7x}{100}$

Percentage of the second number less than the first is,

= (Decrease in number)/(first number) × 100

= $\frac{7x/100}{60x/100}\times 100$

= $\frac{7}{60}\times 100$

= 11%

Therefore, 11% is the second number less than the first number.

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