Question

Two numbers are less than a third number by 52% and59% respectively how much percent is the second number less than the first

Answer 1

Answer:

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Answer 2

Second number is 14.58% less than the first number

Given :

Two numbers are less than a third number by 52% and 59% respectively

To find :

The percentage the second number is less than the first number

Solution :

Step 1 of 2 :

Assume the three numbers

Let third number = 100x

Since two numbers are less than a third number by 52% and 59% respectively

Thus we get,

First number = 100x - 52x = 48x

Second number = 100x - 59x = 41x

Step 2 of 2 :

Find the percentage

The difference between first number and second number

= 48x - 41x

= 7x

Hence the required percentage

$\displaystyle \sf = \frac{7x}{48x} \times 100\%$

$\displaystyle \sf = \frac{7}{48} \times 100\%$

$\displaystyle \sf = 14.5833333\%$

$\displaystyle \sf \approx 14.58\%$

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