two numbers are respectively 12 1 /2% and 25% more than third number find what percent is first number of the second number
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Answer:
90%
Step-by-step explanation:
Given that there are two numbers A (say) and B (say) and they are 12.5% and 25% higher than a third number C(say) respectively.
So, we can write A= [1+(12.5/100)]C =1.125C .......(1)
and, B= [1+(25/100)]C = 1.25C ...... (2)
We have to find that what percentage is A of B.
Therefore, from equations (1) and (2), the percentage is given by (A/B)*100% = (1.125C/1.25C)*100% =(0.9)*100% = 90%.
(Answer)
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