Question

two numbers are respectively 20% and 10% more than a third number how much percent is the first numbers more than the second​

Answer 1

Step-by-step explanation:

let x , y and z be the numbers.

x = 1.2z and y = 1.1z, then

x / y = 1.2 / 1.1 ~ 1.09

thus the first number is approximately 9% more then the second.